y^2+4y-140=0

Solution for y^2+4y-140=0 equation:

Simplifying
y2 + 4y + -140 = 0

Reorder the terms:
-140 + 4y + y2 = 0

Solving
-140 + 4y + y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(-14 + -1y)(10 + -1y) = 0

Subproblem 1
Set the factor '(-14 + -1y)' equal to zero and attempt to solve:

Simplifying
-14 + -1y = 0

Solving
-14 + -1y = 0

Move all terms containing y to the left, all other terms to the right.

Add '14' to each side of the equation.
-14 + 14 + -1y = 0 + 14

Combine like terms: -14 + 14 = 0
0 + -1y = 0 + 14
-1y = 0 + 14

Combine like terms: 0 + 14 = 14
-1y = 14

Divide each side by '-1'.
y = -14

Simplifying
y = -14
Subproblem 2
Set the factor '(10 + -1y)' equal to zero and attempt to solve:

Simplifying
10 + -1y = 0

Solving
10 + -1y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-10' to each side of the equation.
10 + -10 + -1y = 0 + -10

Combine like terms: 10 + -10 = 0
0 + -1y = 0 + -10
-1y = 0 + -10

Combine like terms: 0 + -10 = -10
-1y = -10

Divide each side by '-1'.
y = 10

Simplifying
y = 10
Solution
y = {-14, 10}